5x+2[3(x-4)+1]=33

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Solution for 5x+2[3(x-4)+1]=33 equation:


Simplifying
5x + 2[3(x + -4) + 1] = 33

Reorder the terms:
5x + 2[3(-4 + x) + 1] = 33
5x + 2[(-4 * 3 + x * 3) + 1] = 33
5x + 2[(-12 + 3x) + 1] = 33

Reorder the terms:
5x + 2[-12 + 1 + 3x] = 33

Combine like terms: -12 + 1 = -11
5x + 2[-11 + 3x] = 33
5x + [-11 * 2 + 3x * 2] = 33
5x + [-22 + 6x] = 33

Reorder the terms:
-22 + 5x + 6x = 33

Combine like terms: 5x + 6x = 11x
-22 + 11x = 33

Solving
-22 + 11x = 33

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '22' to each side of the equation.
-22 + 22 + 11x = 33 + 22

Combine like terms: -22 + 22 = 0
0 + 11x = 33 + 22
11x = 33 + 22

Combine like terms: 33 + 22 = 55
11x = 55

Divide each side by '11'.
x = 5

Simplifying
x = 5

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